Background
An object partially or fully submerged in water displaces certain amount or volume of water. The since matter has properties of mass and volume, it imparts some lift force to the object submerged in it. An object displaces its self-weight archemedes principle. This principle guides the communication of forces on the bodies floating on water and other fluids. The experiment aims at proving the archemedes theory of the floatation of the bodies that floats on or submerged in fluids. The success of the experiment shall shows that the theory is true while the negative of the experiment will disapprove the theory.
Equipment
The report lists the equipments that the experiment applied as the following:
Ring stand or the spring scale string, rock or hook mass,600-ml beaker ,500ml graduated cylinder, clear container or 3 gallon bucket, water, masking tape, chunk of wood, modeling clay, toy boat capable of 1200 gram cargo or 9 inch aluminum cake pan.100g mass or lead fishing sinkers.
Procedure
Step 1:
• mount the balance on top of a vertical rod
• Weigh objects suspended underneath the balance of pan.
• A person can use such a balance or spring scale to determine the weight of an object (rock or hook mass ) that is first out of water, and then when completely under water (submerged).
Note: The difference in weights is the buoyant force.
• Record the weights and the buoyant force.
Weight of object out of water=…?
Weight of object in water=…?
Buoyant force on the object=…?
Step2:
• Devise a method to find the volume of water displaced by the object.
• Record the volume of water displaced. Compute the mass and the weight of this water.
Note: (Remember, 1.0ml of water has a mass of 1.0g and a weight of 0.0098N.)
Volume of water displaced = …?
Mass of water displaced = …?
Observations/results of the experiment
The findings of the experiment regarding the given inputs take the amounts stated below.
Weight of object out of water was=0.65N
Weight of object in water was=0.54N
Buoyant force on the object was=0.11N
Has a mass of 1.0g and a weight of 0.0098N.)
Calculations
Note density of the water =1000kg/m3
Volume of water shifted is equivalent to the Buoyant force on the object=0.11N
Hence the volume=mass /density
Volume of water =0.011kg/1000kgm3
=0.000011m3
Mass displaced is =buoyant force/gravitational pull
=0.11N/9.98N/kg
=0.01102kg=11.02g
Conclusion
From the analysis and the calculation note that from archemedes principle; a person establishes that a body displaces the weight equivalent to its weight. In addition, if the body sinks then the buoyancy or up thrust force acting on the body is equivalent to the weight of the displaced volume of fluid. Volume and the mass of the fluid displaced. Knowledge of the density of the fluid facilitates the achievement of the quantities. The gravitational force is 9.98Nkg-1
